Sep 05, 2010 · calculate the % ionic character? if LiF bond length id 0.156 nm and observed dipole is 6.32Debye. Answer Save. 1 Answer. Relevance. DanielHeyward.
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Given that the dipole moment and bond length of HF are 1.92 D and 91.7 p m, respectively, calculate the percent ionic character of the molecule. ( 1 D = 3.336 × 10 − 30 C m) where μ is the experimentally measured dipole moment (in C m ), e the electronic charge, and d the bond length in meters.
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Ionic bonds are those between a metal (lithium) and a nonmetal (hydrogen). The bonding between H and Cl is covalent bonding, so the fact that the bond between Li and H is actually ionic should let you know that LiH is more ionic. The same goes for the next part of that question, where it asks if MgCl2 or PCl3 is more ionic.
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Nov 13, 2017 · If you count the delta E.N. of those molecules the number should be 1.9 for HF, 0.9 for HCl, 0.7 for HBr, and 3.0 for LiF. In this case, lif would be the one with highest percent ionic character. New questions in Chemistry
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The answer lies in the fact that percent ionic character can be interpreted in different ways. In this course, we will use electronegativity differences as you have done. The graph on page 92 takes the internuclear bond distance into account, and thus defines the percent ionic character as function of the resulting dipole moment.